Author: Dr. Vikas Jasrotia

Organic Chemistry Important Explanations Organic Explanations S.No 1 Bond enthalpy decreases as: CH3-F > CH3-Cl > CH3-Br > CH3-I Because the C-X bond length increases from F to I due to the greater size. 2 Phenol cannot be converted into chlorobenzene by using HCl Because the C-O bond in phenol has partial double bond character, and the OH group is attached to a sp2 carbon 3 Thionyl chloride is preferred to convert ROH into RCl Because the side products are gases, and the product can be obtained as pure 4 30 alcohols can easily be converted into alkyl…

THERMODYNAMICS PDF THERMODYNAMICS PDF Introduction Chemical thermodynamics deals with the relationship between various forms of energy in a process. Thermodynamics deals with macroscopic properties. This chapter introduces a major subsidiary thermodynamic property, the Gibbs free energy which lets us express the spontaneity of a process in terms of the properties of the system. This chapter helps to explain why gases expand or diffuse. System and Surrounding 1. System: A specific portion of the universe under study that is separated from the rest of the universe with a boundary is called a system. 2. Surroundings: The rest of the universe which…

States of Matter Class 11 Notes PDF States of Matter Class 11 Notes PDF Gas is the state of matter in which molecules are always in random motion. Intermolecular interactions are extremely small (almost negligible) as compared to other states like solid and liquid. Gases are highly compressible states of matter and their state of diffusion is maximum. Gases have their own importance in the living world. Air is a gaseous mixture of oxygen, nitrogen, CO2, Ar, etc. Intermolecular Forces Intermolecular forces are the forces of attraction and repulsion between interacting particles. This term does not include the electrostatic forces…

Chemistry Class 11 Chapter 2 Question Number 2.26 and 2.27 Question 2.26: An atom of an element contains 29 electrons and 35 neutrons. Deduce (i) the number of protons and (ii) the electronic configuration of the element. Answer 2.26: (i) For an atom to be neutral, the number of protons is equal to the number of electrons. The number of protons in the atom of the given element = 29 (ii) The electronic configuration of the atom is 1s2 2s2 2p6 3s2 3p6 4s1 3d10 Question 2.27: Give the number of electrons in the species H2+,  H2, and O2+ Answer…

Chemistry Class 11 Chapter 2 Question Number 2.24 and 2.25 Question 2.24: What is the lowest value of n that allows g orbitals to exist? Answer 2.24: For g-orbitals, l = 4. As for any value ‘n’ of the principal quantum number, the Azimuthal quantum number (l) can have a value from zero to (n – 1). For l = 4, minimum value of n = 5 Question 2.25: An electron is in one of the 3d orbitals. Give the possible values of n, l, and ml for this electron. Answer 2.25: For the 3d orbital: Principal quantum number…

Difference Between Mixture and Compound Difference Between Mixture and Compound Mixture Compound 1. Nature: In a mixture, two or more elements or compounds are mixed, such that they do not combine chemically 1. Nature: In a compound, two or more elements unite chemically. 2. Structure: The mixture does not have a definite structure. 2. Structure: Compounds have a definite structure. 3. Composition: In the case of a mixture, their constituents can be present in any ratio, i.e., they have variable composition. 3. Compositions: In the case of a compound, the constituents are present in a fixed ratio by weight. 4.…

Atoms and Molecules Class 9 NCERT Atoms and Molecules Class 9 NCERT Que 1. Give the unit to measure the size of an atom and give the size of the hydrogen atom. Ans 1. The unit to measure the size of an atom is a nanometre, size of the hydrogen atom is 10-10m. Que 2. What is IUPAC, give its one function? Ans 2. IUPAC is the International Union for Pure and Applied Chemistry. It gives the names of elements. Que 3. Give the Latin names for sodium, potassium, gold, and mercury. Ans 3.  Sodium → Natrium Gold → Aurum…

Atoms and Molecules Class 9 Questions (MCQs) Atoms and Molecules Class 9 Questions Que 1. Which of the following correctly represents 360 g of water? (i) 2 moles of water (ii) 20 moles of water (iii) 6.022 × 1023 molecules of water (iv) 1.2044 × 1025 molecules of water (a) (i) (b) (i) and (iv) (c) (ii) and (iii) (d) (ii) and (iv) Que 2. Which of the following statements is not true about an atom? (a) Atoms are not able to exist independently. (b) Atoms are the basic units from which molecules and ions are formed. (c) Atoms are…

Question 2.12: Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate the threshold frequency (ν0) and work function (W0) of the metal. https://www.youtube.com/watch?v=g26ITvZzxEI&t=10s Question 2.12: Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate the threshold frequency (ν0) and work function (W0) of the metal. Answer 2.12: Threshold wavelength of radiation (Λ0) = 6800 Å = 6800 × 10–10 m = 6.8 × 10–7m Threshold frequency (ν0) of the metal ν0 = c/Λ0 c = 3…

Question 2.11: A 25-watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second. https://www.youtube.com/watch?v=i1KVhxl01OU&t=152s Question 2.11: A 25-watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second. Answer 2.11: Power of bulb, P = 25 Watt = 25 Js–1 The energy of one photon, E = hν = hc/Λ Substituting the values of h, c, and Λ in the above relation E = (6.626 × 10-34) (3 × 108)/0.57 × 10-6 E = 34.87 × 10–20 J Rate of emission of quanta…