**Chemistry Class 11 Chapter 2 Question Number 2.24 and 2.25**

**Question 2.24: What is the lowest value of n that allows g orbitals to exist?**

**Answer 2.24:** For g-orbitals, l = 4.

As for any value ‘n’ of the principal quantum number, the Azimuthal quantum number (l) can

have a value from zero to (n – 1).

For l = 4, minimum value of n = 5

**Question 2.25: An electron is in one of the 3d orbitals. Give the possible values of n, l, and ml for this **

**electron.**

**Answer 2.25:** For the 3d orbital:

Principal quantum number (n) = 3

Azimuthal quantum number (l) = 2

Magnetic quantum number (ml) = – 2, – 1, 0, 1, 2

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