Facebook X (Twitter) Instagram
    ScienceMotive
    • Class 9
      • Matter in Our Surroundings
      • Is Matter Around Us Pure
      • Atoms and Molecules
      • Structure of the Atom
      • The Fundamental Unit of Life
    • Class 10
      • Chapter 1: Chemical Reactions and Equations
      • Chapter 2: Acids, Bases & Salts
      • Chapter 3: Metals & Non-Metals
      • Chapter 4: Carbon and its Compounds
      • Chapter 5: Periodic Classification of Elements
      • Chapter 6: Life Processes
      • Chapter 7: Control and Coordination
      • Chapter 8: How Do Organisms Reproduce?
      • Chapter 9: Heredity and Evolution
      • Chapter 10: Light – Reflection and Refraction
      • Chapter 11: Human Eye and the Colourful World
      • Chapter 12: Electricity
      • Chapter 13: Magnetic Effects of Electric Current
      • Chapter 14: Sources of Energy
      • Chapter 15: Our Environment
      • Chapter 16: Management of Natural Resources
    • Class 11
      • Chemisrty 11
        • Chapter – 1 Some Basic Concepts of Chemistry
        • Chapter – 2 Structure Of Atom
        • Chapter – 3 Classification of Elements and Periodicity in Properties
        • Chapter – 4 Chemical Bonding and Molecular Structure
        • Chapter – 5 States of Matter
        • Chapter – 6 Thermodynamics
        • Chapter – 7 Equilibrium
        • Chapter – 8 Redox Reaction
        • Chapter – 10 s-Block Elements
        • Chapter – 13 Hydrocarbons
    • Class 12
      • Chemistry 12
        • The Solid State
        • Solutions
        • Electrochemistry
        • Chemical Kinetics
        • Surface Chemistry
        • p – Block Elements
        • d & f Block Elements
        • Coordination Compounds
        • Haloalkanes and Haloarenes
        • Alcohols, Phenols and Ethers
        • Aldehydes, Ketones and Carboxylic Acids
        • Amines
        • Biomolecules
        • Polymers
        • Chemistry in Everyday Life
    • Practice Questions
      • +1
      • +2
    • Test Series
      • Class 9 Test Series
      • Class 10 Test Series
      • Class 11 Test Series
      • Class 12 Test Series
    • World
      • Current Affairs
      • General Knowledge
    ScienceMotive
    Home » Chapter Electrochemistry Test Paper – 1(Solutions)

    Chapter Electrochemistry Test Paper – 1(Solutions)

    Dr. Vikas JasrotiaBy Dr. Vikas JasrotiaMay 13, 2022Updated:May 13, 2022No Comments
    Share
    Facebook WhatsApp Telegram Twitter Email

    Chapter Electrochemistry Test Paper – 1 (Solutions)

    Chapter Electrochemistry Test Paper (Solutions)

    Ans 1. 

    Ans 2.

    Ans 3. (A). Any redox reaction would occur spontaneously, if the cell emf is positive.

    Ans 4. (C).  2H2O → 2H2(g) + O2(g)
    2x                           x
    ∴ 3x = 0.168
    ∴ x = 0.056L
    VH2= 2x = 0.112L,   VO2= x = 0.056L
    11.2L of H2 at STP = 1F
    0.112L of H2 at STP = 0.01F
    0.056L of O2 at STP = 0.01F
    ∴ The amount of electricity passed
    = 0.01F = 965C

    Ans 5. (C). The type of electrode Pb | PbSO4(s) | H2SO4 used in acid storage cell is metal–insoluble salt–anion electrode.

    Chapter Electrochemistry Test Paper (Solutions)

    Ans 6. (D). At pressure 10–14 atm Pt, H2 | H2O act as a S.H.E.

    Ans 7. (A). We know that the reducing power of a metal depends upon its tendency to lose electrons. Thus lower the reduction potential, the more the tendency to get oxidized, and thus more will be the reducing power.
    Hence increasing order of reducing power is: Ag < Hg < Cr < Mg < K

    Ans 8. (B). The reaction Zn2+ + 2e– → Zn has a standard potential of – 0.76 V. This means Zn is a reducing agent.

    Ans 9. (B).

    = 0.02
    ⇒ Ka (CH3COOH) = Ca2 = 0.04 × (4.8)
    ⇒ pKa = 6 – log 24 = 6 – 4 × 0.3 = 4.8
    ⇒ pKb (CH3COO–) = 14 – pka = 14 – 4.8 = 9.2

    Ans 10. (A). For spontaneous cell reaction in galvanic cell:
    Eºcell > 0; ΔGº < 0; Quotient Q < Kc

    Ans 11. (A). When an electric current is applied to an aqueous solution of FeCl2 and ZnCl2 reaction at the cathode:
    Fe2+(aq) + 2e–(aq) → Fe(s) E°red = – 0.44V

    Ans 12. (B). The free-energy change and the cell potential have opposite signs.    

    Ans 13. (D). The given reaction is a reduction reaction.

    Ans 14. (D). The standard oxidation potential is
    1.14 V – (–0.76 V) = 1.90 V

    Ans 15. (A). Cell reaction is:
    Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)
    Here n = 2
    Eºcell = Eºcathode – Eºanode (On the basis of reduction potential)
    = + 0.34 – (– 0.76) = 1.10 V
    We know that: Wmax = ΔGº = – nFEº
    = – (2 mol) × (96500 C mol) × (1.10 V)
    = – 212300 J
    or Wmax = – 212300 J.

    Chapter Electrochemistry Test Paper (Solutions)

    Ans 16. (A) A half-cell is prepared by dipping an Ag electrode in a solution containing KCl and some AgCl. Half-cell is used as a cathode during the cell reaction. The quantity of AgCl will decrease.

    Ans 17. (D)
    Reason: The conductivity of solutions of different electrolytes in the same solvent and at a given temperature differs due to the size and charge of the ions in which they dissociate, the concentration of ions, and the ease with which the ions move under a potential gradient.

    Ans 18. (A) and (B)
    Reason: Electrolysis of CuSO4 can be represented by two half-cell reactions these occurring at cathode and anode, respectively, as given below:
    At cathode: Cu2+ + 2e– → Cu(s)
    At anode: Cu(s) → Cu2+ + 2e−
    On dissolution of CuSO4 in water will dissociate as Cu+2, SO4 2–, H+, OH–.

    Ans 19. (A)
    Reason: Copper does not liberate hydrogen from acids because copper lies below hydrogen in electrochemical series. So, copper does not have sufficient electrode potential to liberate elemental hydrogen from compounds in which the oxidation state of hydrogen is +1

    Ans 20. (C)
    Reason: Ecell is an intensive property and it does not depend upon the number of particles but ΔrG of the cell reaction is an extensive property because this depends upon the number of particles.
     

    Class 12 Chapter Electrochemistry Test Paper – 1

     

    Advertisement
    Chapter Electrochemistry Test Paper (Solutions)
    Share. Facebook Twitter Pinterest LinkedIn Tumblr Email
    Dr. Vikas Jasrotia
    • Website

    Related Posts

    (Solutions) Chemical Kinetics Class 12 Test – 1

    June 14, 2022

    Chemical Kinetics Class 12 Test – 1

    June 8, 2022

    Answers Electrochemistry Important Questions – Class 12

    June 7, 2022

    Leave A Reply Cancel Reply

    READ ALSO

    Question 2.12: Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate the threshold frequency (ν0) and work function (W0) of the metal.

    September 29, 2023

    Question 2.11: A 25-watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second.

    September 27, 2023

    Question 2.10: Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. Calculate the ionization energy of sodium in kJ mol–1.

    September 26, 2023

    Question 2.9: A photon of wavelength 4 × 10–7 m strikes on the metal surface, the work function of the metal is 2.13 eV. Calculate (i) the energy of the photon (eV), (ii) the kinetic energy of the emission, and (iii) the velocity of the photoelectron (1 eV= 1.6020 × 10–19 J).

    September 25, 2023
    +1

    Question 2.12: Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate the threshold frequency (ν0) and work function (W0) of the metal.

    By Dr. Vikas JasrotiaSeptember 29, 2023

    Question 2.12: Electrons are emitted with zero velocity from a metal surface when it is…

    +1

    Question 2.11: A 25-watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the rate of emission of quanta per second.

    By Dr. Vikas JasrotiaSeptember 27, 2023

    Question 2.11: A 25-watt bulb emits monochromatic yellow light of wavelength of 0.57µm. Calculate the…

    +1

    Question 2.10: Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium atom. Calculate the ionization energy of sodium in kJ mol–1.

    By Dr. Vikas JasrotiaSeptember 26, 2023

    Question 2.10: Electromagnetic radiation of wavelength 242 nm is just sufficient to ionize the sodium…

    Advertisement
    Advertisement
    Facebook X (Twitter) Instagram Pinterest YouTube
    • Disclaimer
    • Contact Us
    • Privacy Policy 
    • Terms and Conditions
    © 2023 All Rights Reserved ScienceMotive.

    Type above and press Enter to search. Press Esc to cancel.