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    Home » Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2

    Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2

    Dr. Vikas JasrotiaBy Dr. Vikas JasrotiaSeptember 19, 2022No Comments
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    Que. Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3(s) + 2 HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l). What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?
    Ans. 0.75 M means 0.75 mol of HCl is present in 1 L of solution
    1 Mol of HCl weighs = 1 + 35.5 = 36.5 g
    0.75 mol of HCl weighs = 0.75 × 36.5 = 27.37 g
    ⸫ 27.37 g of HCl is present in 1000 ml (1 L) of solution
    1000 ml of solution contains HCl = 27.37 g
    1 ml of solution contain HCl = 27.37/1000 = .02737 g
    25 ml of solution contain HCl = 0.2737 × 25 = 0.684 g
    We have the chemical equation
    CaCO3 + 2 HCl à CaCl2 + CO2 + H2O
    2 mol of HCl (i.e 2 × 35.5 = 71 g) react with 1 mol of CaCO3 (i.e 100 g)
    ⸫ 71 g of HCl reacts with CaCO3 = 100 g
    1 g of HCl reacts with CaCO3 = 100/71 = 1.408 g
    ⸫ 0.684 g of HCl reacts with CaCO3 = 1.408 × 0.684 = 0.963 g

     

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