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    Home » Arrange the following in each as instructed (i)    O, F, S, Cl, N in order of increasing strength of hydrogen bonding (X — H – X). (ii)  N2, O2, F2, Cl2 in increasing order of bond dissociation energy.

    Arrange the following in each as instructed (i)    O, F, S, Cl, N in order of increasing strength of hydrogen bonding (X — H – X). (ii)  N2, O2, F2, Cl2 in increasing order of bond dissociation energy.

    Dr. Vikas JasrotiaBy Dr. Vikas JasrotiaOctober 10, 2022Updated:October 10, 2022No Comments
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    Que: Arrange the following in each as instructed
    (i)    O, F, S, Cl, N in order of increasing strength of hydrogen bonding (X — H – X).
    (ii)  N2, O2, F2, Cl2 in increasing order of bond dissociation energy.
    Ans: (i)  Strength of hydrogen bonding depends on the electronegativity of the atom linked with hydrogen. Thus the order is S < Cl < N < O < F
    (ii) The increasing order is F2 < Cl2 < O2 < N2. Both fluorine and chlorine atoms in F2 and Cl2 possess three non-bonded electron pairs each. Due to the small size of fluorine, there is larger repulsion between non-bonded electrons in comparison to chlorine. Thus, F2 has lesser dissociation energy than Cl2. In oxygen, two non-bonded electron pairs are present, i.e., less repulsion than Cl2 and in nitrogen only one electron pair is present, i.e., minimum repulsion is present. Hence, N2 has maximum stability.

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