NCERT Class 12 Chemistry Chapter 2 Exercise Solutions Archives

NCERT Class 12 Chemistry Chapter 2 Exercise Solutions

Mar 26, 2021 Dr. Vikas Jasrotia

NCERT Class 12 Chemistry Chapter 2 Exercise Solutions Que 1. Define the term solution. How many types of solutions are formed? Write briefly about each type with an example. Ans…

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NCERT Class 12 Chemistry Chapter 2 Exercise Solutions

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Discuss the various reactions involved in the Solvay process

An element occupies group number 1 and period number 3. This element heated in the air gives compound A. With water, it gives compound B which is a strong base. The reaction of B with ammonia gives compound C, which is used as a reducing agent in organic chemistry. Identify the element A, B, and C.

What is entropy? Why is the entropy of a substance taken as zero at 0K? Calculate the ΔG for the reaction? N2(g) + 3H2(g) → 2NH3(g) at 298K The value of equilibrium constant (K) is 6.6 × 105, R = 8.314 JK-1mol-1.

(Solutions) Chemical Kinetics Class 12 Test – 1

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Tag: NCERT Class 12 Chemistry Chapter 2 Exercise Solutions

NCERT Class 12 Chemistry Chapter 2 Exercise Solutions

You missed

Discuss the various reactions involved in the Solvay process

An element occupies group number 1 and period number 3. This element heated in the air gives compound A. With water, it gives compound B which is a strong base. The reaction of B with ammonia gives compound C, which is used as a reducing agent in organic chemistry. Identify the element A, B, and C.

What is entropy? Why is the entropy of a substance taken as zero at 0K? Calculate the ΔG for the reaction? N2(g) + 3H2(g) → 2NH3(g) at 298K The value of equilibrium constant (K) is 6.6 × 105, R = 8.314 JK-1mol-1.

(Solutions) Chemical Kinetics Class 12 Test – 1